- Home
- Standard 11
- Physics
A mosquito is moving with a velocity $\overrightarrow{ v }=0.5 t ^{2} \hat{ i }+3 t \hat{ j }+9 \hat{ k }\, m / s$ and accelerating in uniform conditions. What will be the direction of mosquito after $2 \,s$ ?
$\tan ^{-1}\left(\frac{2}{3}\right)$ from $x-$ axis
$\tan ^{-1}\left(\frac{2}{3}\right)$ from $y$ -axis
$\tan ^{-1}\left(\frac{5}{2}\right)$ from $y$ -axis
$\tan ^{-1}\left(\frac{5}{2}\right)$ from $x$ -axis
Solution
Given :
$\overrightarrow{ v }=0.5 t ^{2} \hat{ i }+3 t \hat{ j }+9 \hat{ k }$
$\overrightarrow{ v }_{ at\,t =2}=2 \hat{ i }+6 \hat{ j }+9 \hat{ k }$
$\therefore$ Angle made by direction of motion of mosquito will be,
$\cos ^{-1} \frac{2}{11}($ from $x$ -axis $)=\tan ^{-1} \frac{\sqrt{117}}{2}$
$\cos ^{-1} \frac{6}{11}($ from $y$ -axis $)=\tan ^{-1} \frac{\sqrt{85}}{6}$
$\cos ^{-1} \frac{9}{11}($ from $z$ -axis $)=\tan ^{-1} \frac{\sqrt{40}}{9}$
None of the option is matching.
Hence this question should be bonus.