3-2.Motion in Plane
hard

A mosquito is moving with a velocity $\overrightarrow{ v }=0.5 t ^{2} \hat{ i }+3 t \hat{ j }+9 \hat{ k }\, m / s$ and accelerating in uniform conditions. What will be the direction of mosquito after $2 \,s$ ?

A

$\tan ^{-1}\left(\frac{2}{3}\right)$ from $x-$ axis

B

$\tan ^{-1}\left(\frac{2}{3}\right)$ from $y$ -axis

C

$\tan ^{-1}\left(\frac{5}{2}\right)$ from $y$ -axis

D

$\tan ^{-1}\left(\frac{5}{2}\right)$ from $x$ -axis

(JEE MAIN-2021)

Solution

Given :

$\overrightarrow{ v }=0.5 t ^{2} \hat{ i }+3 t \hat{ j }+9 \hat{ k }$

$\overrightarrow{ v }_{ at\,t =2}=2 \hat{ i }+6 \hat{ j }+9 \hat{ k }$

$\therefore$ Angle made by direction of motion of mosquito will be,

$\cos ^{-1} \frac{2}{11}($ from $x$ -axis $)=\tan ^{-1} \frac{\sqrt{117}}{2}$

$\cos ^{-1} \frac{6}{11}($ from $y$ -axis $)=\tan ^{-1} \frac{\sqrt{85}}{6}$

$\cos ^{-1} \frac{9}{11}($ from $z$ -axis $)=\tan ^{-1} \frac{\sqrt{40}}{9}$

None of the option is matching.

Hence this question should be bonus.

Standard 11
Physics

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